Complex Expression - Manipulate the expression until you can sketch it... (1 Viewer)

[Utility]

The Q. is to sketch the region formed by this expression --> arg(z + 2 - 3i) = π / 6.

Let z = x + iy...

 

[HeroicPandas]

arg( x+2 + i(y-3) = pi/6 right?

now arctan[(y-3)/(x+2)] = pi/6

(y-3)/(x+2) = 1/(root3)

note that x =/= -3

y = 3 + 1/root3 (x+2)

when x= -2, y = 3 (i.e. (-2,3) is a hollow point)

and its a line having a an argument of pi/6 to the horizontal line y =3

 

[cineti970128]

you realise in the exam they are not going to give you marks on the line expression.

just poing an empty dot on (-2,3) and draw a line with pi/6 degree above the horizontal line

 

[HeroicPandas]

you realise in the exam they are not going to give you marks on the line expression.

just poing an empty dot on (-2,3) and draw a line with pi/6 degree above the horizontal line

Read what the OP is asking naughty boy. "Manipulate the expression until you can sketch it..."

Think b4 u post...