Complex Number Vector (1 Viewer)

[CLD]

Complex Number Vector

Sorry, I am not 100% sure but... it was a vector question:

OABC is a square (where A =z1 B=z2 C=z3) obv. 0 = (0,0)

Arg(a) = pi/4

Area of this square is 8 u^2.

I think Ive got this but can I just double check with you guys~? Thanks.​

 

[carrotsss]

The side lengths of a square of area 8 must be 2√2, so therefore a is 2√2cis(pi/4). Because its a square, angle COA must pi/2, so therefore c is 2√2cis(3pi/4) or 2√2cis(-pi/4), and hence b is a+c for all sides to be equal, so it is 2√2i or 2√2 for each value of c respectively.