B bic New Member Joined Sep 15, 2004 Messages 1 Sep 15, 2004 #1 anybody got any ideas on how to go about this one.. show that every circle that passes through the intersections of the circle x^2 + y^2 = 2 and the straight line y = x can be written in the form (x-h)^2 + (y+h)^2 = 2(1+h^2) thanks
anybody got any ideas on how to go about this one.. show that every circle that passes through the intersections of the circle x^2 + y^2 = 2 and the straight line y = x can be written in the form (x-h)^2 + (y+h)^2 = 2(1+h^2) thanks
E Estel Tutor Joined Nov 12, 2003 Messages 1,261 Gender Male HSC 2005 Sep 15, 2004 #2 x^2 + y^2 - 2 = 0 y - x = 0 Intersection: x^2 + y^2 - 2 + 2h(y-x) = 0, for some constant h. (x-h)^2 - h^2 + (y+h)^2 - h^2 - 2 = 0 (x-h)^2 + (y+h)^2 = 2(1+h^2)
x^2 + y^2 - 2 = 0 y - x = 0 Intersection: x^2 + y^2 - 2 + 2h(y-x) = 0, for some constant h. (x-h)^2 - h^2 + (y+h)^2 - h^2 - 2 = 0 (x-h)^2 + (y+h)^2 = 2(1+h^2)
