• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

Difficult plane geometry question (1 Viewer)

c_james

Viva La Merchandise!
Joined
Mar 15, 2004
Messages
512
Gender
Male
HSC
2005
Any help with this one would be much appreciated:

 

Winston

Active Member
Joined
Aug 30, 2002
Messages
6,128
Gender
Undisclosed
HSC
2003
Is any other information given for the question?
 

c_james

Viva La Merchandise!
Joined
Mar 15, 2004
Messages
512
Gender
Male
HSC
2005
No. I'm quite sure it can be done, as my teacher went through it in class (I didn't get a chance to copy down his solutions though, as the bell rang).
 

Winston

Active Member
Joined
Aug 30, 2002
Messages
6,128
Gender
Undisclosed
HSC
2003
Well seeing the Perp Bisector is BE, then it cuts that triangle up, so that BEA = BEC = 90 Degrees, and the other four remaining angles are respectively equal to 45 Degrees, and then and to get ACD you just do 180 - 45 degrees, since it's on a straight line.

so ACD = 135 Degrees, and we know that BAC = 45 Degrees, so add them together and you get 180 degrees. and 2 x BEC = 180 so yeah.

I don't think i've proved it right lol, cause i assumed the two triangles remaining angles are cut up evenly to 45 degrees.
 

untamedanimal

Member
Joined
Feb 27, 2004
Messages
243
If you are given that AB = BC the Winston's solution would be correct, otherwise i dont think its provable
 

...

^___^
Joined
May 21, 2003
Messages
7,723
Location
somewhere inside E6A
Gender
Male
HSC
1998
u dunno if BE cuts AC perpendicularly, thats the problem, it looks like it is, but theres no info stating it is...
 

c_james

Viva La Merchandise!
Joined
Mar 15, 2004
Messages
512
Gender
Male
HSC
2005
Even if the two triangles were cut up evenly to 45 degrees, that doesn't necessarily mean AB will equal BC. My teacher did it using a bunch of exterior angles theorems, and I remember it was quite a long process. But I'm sure it's provable.
 
Last edited:

Winston

Active Member
Joined
Aug 30, 2002
Messages
6,128
Gender
Undisclosed
HSC
2003
But it would be very hard, i mean i'm pretty sure there should be at least one piece of data, and the crucial item would be knowing that BE is perpendicular.
 

c_james

Viva La Merchandise!
Joined
Mar 15, 2004
Messages
512
Gender
Male
HSC
2005
If only I'd got up off my lazy ass and copied the answers...I'm looking at the paper right now and no other information was provided. I remember my teacher let one of the top angles equal x and used a lot of algebra and such to reach the final answer.
 

Affinity

Active Member
Joined
Jun 9, 2003
Messages
2,062
Location
Oslo
Gender
Undisclosed
HSC
2003
You don't need any additional assumptions.

ACD = CBE + BEC (exterior angle = sum of interior angles)

BEC = EBA + BAC (same reason)

now note that CBE = EBA, subtract the second equation from the first.

ACD - BEC = BEC - BAC
ACD + BAC = 2BEC

moral of the story: Don't dismiss something until you find some concrete counterexample
 
Last edited:

elizabethy

I'm the best !!
Joined
Oct 23, 2002
Messages
1,160
Location
Sydney
Gender
Female
HSC
2003
Originally posted by Affinity

moral of the story: Don't dismiss something until you find some concrete counterexample
this is so true!!
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top