Does anyone know how to do this? Please help (1 Viewer)

T_Brendan_T

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b. now if the train is moving along a horizontal length of railway line at a constant velocity of 80km/h
i. Calculate the energy stored in the mass of the moving train?
ii. How much power is required to stop the train in 150 seconds?
iii. If the total resistance force supplied when all brakes are applied is 310kN, calculate the distance required for the train to stop?

Q3. Bus with mass 9.5 tonnes, what is the required force to start the bus moving forward if the road surface is inclined at 11 degrees and the coefficients of static friction is 0.65
 

cossine

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Continue:
b. now if the train is moving along a horizontal length of railway line at a constant velocity of 80km/h
i. Calculate the energy stored in the mass of the moving train?
ii. How much power is required to stop the train in 150 seconds?
iii. If the total resistance force supplied when all brakes are applied is 310kN, calculate the distance required for the train to stop?

Q3. Bus with mass 9.5 tonnes, what is the required force to start the bus moving forward if the road surface is inclined at 11 degrees and the coefficients of static friction is 0.65
@T_Brendan_T

Here is what I think. Note I have not studied engineering studies.

force = mg*sin(theta) # need to know about mgsin(theta) and mgcos(theta)

=> a = g*sin(theta)
=> v = integral(g*sin(theta))dt
=> v = gsin(theta)t + C = gsin(theta)t # We assume the initial velocity is zero
=> x = (gsin(theta)t^2)/2 + C = (gsin(theta)t^2) /2 # We assume distance traveled is zero

We need to find t when x = 1000

bi) Kinetic energy is given by (1/2)*m*v^2.
ii)
Some definitions from Wikipedia

W: work
f: force
s: displacement
1656771000976.png

Going take a complete stab an say power = kinetic_energy / 150.

It might be best to email your teacher
 

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