Equation of a curve question (1 Viewer)

[idling fire]

Find the equation of the curve through (-60,18), (0,0) and (40,8) presuming it is in the form y=ax^(2n). Answer is y=x^2/200

I tried to make simultaneous equations, but it didn't seem to work for me. Heh, I'm stuck again.

 

[jyu]

Find the equation of the curve through (-60,18), (0,0) and (40,8) presuming it is in the form y=ax^(2n). Answer is y=x^2/200

I tried to make simultaneous equations, but it didn't seem to work for me. Heh, I'm stuck again.

y=ax^(2n) implies (0,0).

Use (-60,18) and (40,8) to set up simul. eqs.

18 = a(-60)^(2n)
8 = a(40)^(2n)

18/8 = (-60/40)^(2n), simplify to
9/4 = (-3/2)^(2n)
9/4 = (9/4)^n
.: n = 1
Sub. into 8 = a(40)^(2n) to find a = 1/200

:wave:

 

[idling fire]

lol ty. I had confused myself with the ^2n stuff.

Thanks for that