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help for Complex no. (1 Viewer)

Thread starter juantheron
Start date Mar 21, 2013

J

juantheron

Active Member

#1

Value of $\displaystyle i^{i^{i^{i................\infty}}}$

where $i = \sqrt{-1}$ is a Complex no.

P

pdang

Member

#2

set the first i to e^(i*pi/2)

J

juantheron

Active Member

#3

To pdang i did not understand how can i calculate after that

would you like to give me full solution.

Thanks

H

HeroicPandas

Heroic!

#4

I was thinking of using e^(lna) = a

P

pdang

Member

#5

$\left(e^{\frac{\pi}{2}i}\right)^i=e^{-\frac{\pi}{2}}\\\text{Continuing this you get}\\\pm i \text{ or }e^{\pm\frac{\pi}{2}}$

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