S star*eyed Member Joined Nov 30, 2005 Messages 53 Gender Female HSC 2006 Jun 11, 2006 #1 PLZ help me with this question the integration with x= 2 and 0 of 1/ (xsquared +4) ANY HELP WOULD BE APPRECIATED!!!!!!!!!!!!!
PLZ help me with this question the integration with x= 2 and 0 of 1/ (xsquared +4) ANY HELP WOULD BE APPRECIATED!!!!!!!!!!!!!
Trev stix Joined Jun 28, 2004 Messages 2,037 Location Pine Palace, St. Lucia, Brisbane. Gender Male HSC 2005 Jun 11, 2006 #2 Use your standard integral table, it's a basic tan<sup>-1</sup>(blah) one.
hyparzero BOS Male Prostitute Joined Sep 10, 2005 Messages 246 Location Wankersville Gender Female HSC 2006 Jun 11, 2006 #3 this is an Inverse Tan Integration I = ∫ 1/(x2 + 4) {x = 0 ; 2} I => arctan(x/2) / 2 {x = 0 ; 2} Therefore I = 1/2 [arctan(1) - arctan(0)] = 1/2 [π/4] Thus I = π/8
this is an Inverse Tan Integration I = ∫ 1/(x2 + 4) {x = 0 ; 2} I => arctan(x/2) / 2 {x = 0 ; 2} Therefore I = 1/2 [arctan(1) - arctan(0)] = 1/2 [π/4] Thus I = π/8
rama_v Active Member Joined Oct 22, 2004 Messages 1,151 Location Western Sydney Gender Male HSC 2005 Jun 11, 2006 #4 Thats not a 2 unit question