hatty
Banned
how do u differentiate 3^x?
i know its 3^xLnx
but can someone please explain to me how so?
thanks
i know its 3^xLnx
but can someone please explain to me how so?
thanks
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help with this Q plz (1 Viewer)
- Thread starter hatty
- Start date
KeypadSDM
B4nn3d
3^x
= e^Ln[3^x]
= e^[xLn[3]]
The rest follows from there.
d/dx 3^x = Ln[3] * e^[xLn[3]]
= Ln[3] * 3^x
= e^Ln[3^x]
= e^[xLn[3]]
The rest follows from there.
d/dx 3^x = Ln[3] * e^[xLn[3]]
= Ln[3] * 3^x
hatty
Banned
you legend
Grey Council
Legend
- Joined
- Oct 14, 2003
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- HSC
- 2004
lol, well put. Its a good description, innit?
*sigh* wish I get 100 in ext 1 maths, and 99 in ext 2 maths.
*sigh* wish I get 100 in ext 1 maths, and 99 in ext 2 maths.