hav u learnt vectors yet? your answer cant be purely imaginary bc your vector clearly has an acute direction
Shit ur right yeah i have learned vectors lemme see whwre i went wronghav u learnt vectors yet? your answer cant be purely imaginary bc your vector clearly has an acute direction
Hmmm where did i go wrongimo use cis form for this
I genuinely have no clueHmmm where did i go wrong
Ik whwre i went wrong it was silly mistake LMAOOHH NVM I SEE IT NOW
Its been around 2.5 monthshey can i ask when ngo started mx2?? has it been a long time or
Its been around 2.5 months
Yeahis that the specialist class
instantly we can write z_2 = sqrt(3)iz_1
Yeah thats what i got in my new answer cos i realised i made a silly mistake in my original one but the solutions said something elseinstantly we can write z_2 = sqrt(3)iz_1
so z_2 -z_1 = z_1(-1+sqrt(3)i)
now z_1 = e^(ix) [im using x instead of theta]
and -1+sqrt(3)i = 2e^i(2pi/3) by conversion to modulus-argument form
thus, z_2 -z_1 = 2e^i(x+2pi/3)