how to solve this? (1 Viewer)

[dls1]

Have an equation in the form

2^x/6^x = ln(.75)/ln(.25)

How do I solve for x?

 

[3unitz]

Have an equation in the form

2^x/6^x = ln(.75)/ln(.25)

How do I solve for x?

(2/6)^x = ln(.75)/ln(.25)
ln (2/6)^x = ln [ln(.75)/ln(.25)]
x ln (2/6) = ln [ln(.75)/ln(.25)]
x = ln [ln(.75)/ln(.25)] / ln (2/6)

 

[dls1]

Thank you very much