I have a headache... (1 Viewer)

[+GriM ReApeR+]

literally...stupid cold weather...

anyways...
Integrate cos^2(2x)...i know you have to use that cos2x=2cos^2(x)-1 property...but wat happens to the "2x" in the integration...if u can understnad what i'm trying to say...argh...stupid headache... >.<

 

[CrashOveride]

cos 4x = cos^2 2x - sin^2 2x

sin^2(2x) = 1 - cos^2(2x)
sub in, rearrange for ur cos^2 (2x)

shud get integral I: 1/2 (cos4x + 1)

Then its over to you

 

[Calculon]

...../
1/2|cos4x + 1 dx
...../

sin4x/8 + x/2 + c

 

[CrashOveride]

Originally posted by Calculon

sin4x/8

1/8sin(4x)...could be misinterpreted the other way

 

[Calculon]

Originally posted by CrashOveride
1/8sin(4x)...could be misinterpreted the other way

that could mean (8sin4x)^-1

 

[CrashOveride]

Lol ok Mr fastidious:

(1/8) sin(4x)