I2I: Photoelectric Effect (1 Viewer)

[Ragerunner]

mmm....Here's a question, I'm not sure If im right. Some may remember it.

A certain metal has a work function of 2.2eV. 2 light beams, blue of 450nm wavelength and orange of 650nm wavelength are shined onto that surface.

Which will have a better chance to emit electrons?

Obviously it's the one with shorter wavelength, thus higher frequency.

Justify your answer with calculations

This one I'm a bit iffy about.

I used the E = hf formula

But How do I convert my answer to eV?

 

[Constip8edSkunk]

it should be on the data sheet

edit: the conversion rate that is

 

[Ragerunner]

alright thanks.

I got the blue light as 2.7eV and the orange light as 1.7 or something eV.

That correct?

 

[-X-]

Im getting 2.7 for the first and 1.9 for the seoond.

 

[ND]

The solution doesn't have to be in eV anyway, you just have to determine which has greater energy.