xXnukerrrXx
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if n is even prove n^2+2n is divisble by 8 thanks
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induction qs (1 Viewer)
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Carrotsticks
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n=2 etc etc.. (remember to use n=2 to begin with because we are testing even numbers).
Hypothesis:
Inductive step (k --> k+2)
^2+2(k+2) \\\\ = k^2 + 4k + 4 + 2k + 4 \\\\ = k^2 + 2k + 4k+8 \\\\ = 8m + 4k+8 \qquad $ but k is an even integer ie: 4k = 8j for some integer j$ \\\\ = 8(m+j+1) \qquad $, completing the inductive step.$ )
Hypothesis:
Inductive step (k --> k+2)