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thanks, that's correct.FinalFantasy said:d@\dr=3\(1-r)^4
@=(1-r)^-3 (3\3)+C=1\(1-r)³+C
@-C=1\(1-r)³
1\(@-C)=(1-r)³
(1\(@-C) )^(1\3)=1-r
r=1-(1\(@-C) )^(1\3)
r(0)=1-1\(-C)^(1\3) =0
1\(-C)^(1\3)=1
1=(-C)^(1\3)
C=-1
.: r=1-1\(@+1)^(1\3)