integration help needed :) (1 Viewer)

[nfreidman]

how do you integrate:



sin2x/[2+sin²x]


cotx between limits, pi/6 and pi/4

thank you

 

[nightweaver066]

For the first one, apply double angle formula to the top so sin2x=2sinxcosx.

Then use the substitution let u = sinx

For the second one, write it as cosx/sinx and notice the numerator is the derivative of the denominator.