Mathematician
Member
- Joined
- Nov 3, 2002
- Messages
- 188
integrate x^2/(x+1)
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when u do it by substitution using u=x+1 and hence converting x^2 to (u-1)^2 and changing du to dx you get -3/2 in the final result.
changing the integral to [(x+1)(x-1) +1]/(x+1) and integrating it this way you get a similar result without the -3/2.
my question is, is the -3/2 in the answer with the first method just part of the constant of the answer ??
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when u do it by substitution using u=x+1 and hence converting x^2 to (u-1)^2 and changing du to dx you get -3/2 in the final result.
changing the integral to [(x+1)(x-1) +1]/(x+1) and integrating it this way you get a similar result without the -3/2.
my question is, is the -3/2 in the answer with the first method just part of the constant of the answer ??