Inverse Trig Equation question (1 Viewer)

DumbPotato123

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How do you solve this equation? I'm absolutely clueless and nothing I've tried has worked so far. The textbook answer is -0.47 (2d.p.) however when you sub it into x it returns −3309.00847.

Thanks in advanced.
 

erucibon

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Firstly, you have it in degrees - radians gives -1
Now, change cos^-1x into pi/2 - sin^-1x, expand, rearrange for quadratic, solve, taking the negative solution gives -0.486 (3dp)
 

DumbPotato123

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Firstly, you have it in degrees - radians gives -1
Now, change cos^-1x into pi/2 - sin^-1x, expand, rearrange for quadratic, solve, taking the negative solution gives -0.486 (3dp)
This was one of the first things I tried, I'm pretty sure it's incorrect though. I checked on desmos which shows the solution to be -0.4672. Did forget about radians though :oops:.
 

erucibon

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This was one of the first things I tried, I'm pretty sure it's incorrect though. I checked on desmos which shows the solution to be -0.4672. Did forget about radians though :oops:.
My bad, I just forgot to sin it as that is sin^-1x= -.486 from quadratic, this will now give -.467
 

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