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Inverse Trig Integration Question (1 Viewer)

rand_althor

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Hey how would you do this question without using substitution?
 
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integral95

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You'll eventually get that answer if you use the substitution u = (x-b)
 

VBN2470

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. Just recognise that it is in the form as a standard inverse sine integral, but recognising this still (implicitly) requires the substitution .

EDIT: Just realised I got beaten above :p
 

InteGrand

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Are the conditions for the integral or the inverse sine function?
Conditions such as: c > 0, and we assume a is positive in your answer (we should actually write |a| strictly speaking, but this is kind of nitpicking).
 

rand_althor

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Conditions such as: c > 0, and we assume a is positive in your answer (we should actually write |a| strictly speaking, but this is kind of nitpicking).
So that's for the inverse sine function?

What is the domain of the inverse sine function?
 

InteGrand

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So that's for the inverse sine function?

What is the domain of the inverse sine function?
I was talking about for the integral.

For example, if c < 0, we would end up with something like this:

(for example).

There, the expression under the square root in the integrand is negative, and we don't deal with these situations in the HSC.

And the domain of is .
 

InteGrand

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Ah okay, that makes sense.

Sorry I meant the domain of
Domain of that is (assuming c > 0) .

This can be simplified to isolate x in the middle, which is probably what you wanted (just make sure you're careful to flip inequality signs if you multiply through by negative numbers).
 
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rand_althor

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If we assume that a > 0, would we need to take two cases for r? I.e r > 0 and r < 0 ?
 

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