Inverse Trig (1 Viewer)

[Kutay]

Hey i was wondering how to get the final answer to the differnitating problem like i cant simplify it

" y = cos ^-1 ( x / 4)"

i get to y` = -1 / 4 (square root (1 - x^2/16)!!!!!!!!!!!!!1


in the book it says the final answer is -1 / root (16 - x^2)

can someone go through the steps from where i am up to help me find out what i am doing wrong well intially how to simpify sorry!!

 

[FinalFantasy]

Hey i was wondering how to get the final answer to the differnitating problem like i cant simplify it

" y = cos ^-1 ( x / 4)"

i get to y` = -1 / 4 (square root (1 - x^2/16)!!!!!!!!!!!!!1


in the book it says the final answer is -1 / root (16 - x^2)

can someone go through the steps from where i am up to help me find out what i am doing wrong well intially how to simpify sorry!!

"i get to y` = -1 / 4 (square root (1 - x^2/16)!!!!!!!!!!!!!1"
y'=-1\4* 1\sqrt [(16-x²)\16]=(-1\4)*4*1\sqrt(16-x²)=-1\sqrt(16-x²)