M Monstar Member Joined Jan 6, 2006 Messages 877 Gender Male HSC 2006 Jun 11, 2006 #1 State the domain and range of y= inverse sin (x^2) y= x inverse cos x y= inverse sin (tanx)
hyparzero BOS Male Prostitute Joined Sep 10, 2005 Messages 246 Location Wankersville Gender Female HSC 2006 Jun 11, 2006 #2 Here are some hints: a) y = arcsin(x2) => x2 = sin(y) b) y = xarccos(x) => x = cos(y/x) c) y = arcsin(tan(x)) => tan(x) = sin(y) go from there
Here are some hints: a) y = arcsin(x2) => x2 = sin(y) b) y = xarccos(x) => x = cos(y/x) c) y = arcsin(tan(x)) => tan(x) = sin(y) go from there
M Monstar Member Joined Jan 6, 2006 Messages 877 Gender Male HSC 2006 Jun 11, 2006 #3 first of all.. wtf is a "arc" i have never come across this.
P pLuvia Guest Jun 11, 2006 #4 arctanx=inverse tanx=tan-1x arcsinx=inverse sinx=sin-1x arccosx=inverse cosx=cos-1x Another way of saying inverse (something)
arctanx=inverse tanx=tan-1x arcsinx=inverse sinx=sin-1x arccosx=inverse cosx=cos-1x Another way of saying inverse (something)
R Riviet . Joined Oct 11, 2005 Messages 5,593 Gender Undisclosed HSC N/A Jun 12, 2006 #5 Monstar said: first of all.. wtf is a "arc" i have never come across this. Click to expand... I believe this is the conventional way that American mathematicians call it.
Monstar said: first of all.. wtf is a "arc" i have never come across this. Click to expand... I believe this is the conventional way that American mathematicians call it.
M Monstar Member Joined Jan 6, 2006 Messages 877 Gender Male HSC 2006 Jun 12, 2006 #6 neeed more heelpp