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Logs! (1 Viewer)

skankit

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argh, does anyone else really hate logs?
for some reason, i never seem to get the answers right...! i dont get it..!!
grrrrr
:chainsaw:
 

KeypadSDM

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I love 'em

If you're finding them troublesome, just learn the rules off by heart, and they'll be simple.

Log_a[b^c] = c * Log_a
Log_a = Log_c/Log_c[a]
Log_a + Log_a[c] = Log_a[bc]
Log_a - Log_a[c] = Log_a[b/c]

Now these ones are just extras which are useful to know:

Log_a * Log_b[a] = 1
a^(1/Log_b[a]) = b

And I forgot the most important one, the very definition of a log.

a = b^(Log_b[a])
 
Last edited:

Giant Lobster

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Originally posted by ...
wtf r u doing here!!!!!!!!
LOL! what a way to greet someone :D
just cos shes an english mod doesnt mean she's not allowed to help ppl with logs. :p
 

Grey Council

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Hokay, just clearing this up a bit, and adding a few more rules.

Basics first:
log<sub>b</sub>MN = log<sub>M</sub> + log<sub>b</sub>N
log<sub>b</sub>M/N = log<sub>M</sub> - log<sub>b</sub>N
log<sub>b</sub>b = 1
log<sub>b</sub>1 = 0
log<sub>b</sub>b<sup>k</sup> = k


What Keypad posted, but tidied up a bit (easier to read):
Log<sub>a</sub>b<sup>c</sup> = c * Log<sub>a</sub>b
Log<sub>a</sub>b = Log<sub>c</sub>b / Log<sub>c</sub>a
Log<sub>a</sub>b * Log<sub>b</sub>a = 1
a<sup>1/Log_b[a]</sup> = b
a = b<sup>Log_b[a]</sup>

YAY to the QUICKEDIT feature. :D
and if i made a mistake, please let me know.

Learn all those by heart, you'll have a lot less difficulty. And no, learn off by heart doesn't mean rote learn all of them. Try to understand em. As in think about it for a bit, 'understand' it, and you won't forget it. Logs laws aren't all that hard to learn. Unlike trig rules. :-\
 
Last edited:

Grey Council

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you like em? Easy to read, and i don't mind if you print it and give it to your students. :p

but we should have this stickied somewhere. So many people ask for this. I myself didn't know any of them till the yearlies for year 11.
 

victorling

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Originally posted by Grey Council
you like em? Easy to read, and i don't mind if you print it and give it to your students. :p

but we should have this stickied somewhere. So many people ask for this. I myself didn't know any of them till the yearlies for year 11.
i haven't got much students yet(3 at this moment)..lol
:) :) :)
 

Grey Council

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ah well. They'll get more when the word spreads around.

Thing is, we can't tell if your a good TEACHER. I mean, sure, you can be good at maths, but teaching is a talent. It doesn't really come with knowledge. :( You can have a person getting a UAI of 70, but if he inspires his STUDENTS to work, he is a successful teacher. Cause its the student working that will help the student. If the student doesn't work, tuition won't help.
and don't take that wrong. I'm just observing.
 

victorling

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Originally posted by Grey Council
ah well. They'll get more when the word spreads around.

Thing is, we can't tell if your a good TEACHER. I mean, sure, you can be good at maths, but teaching is a talent. It doesn't really come with knowledge. :( You can have a person getting a UAI of 70, but if he inspires his STUDENTS to work, he is a successful teacher. Cause its the student working that will help the student. If the student doesn't work, tuition won't help.
and don't take that wrong. I'm just observing.

u r very correct
thats really the truth
 

KeypadSDM

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log<sub>b</sub>MN = log<sub>b</sub>M + log<sub>b</sub>N
log<sub>b</sub>M/N = log<sub>b</sub>M - log<sub>b</sub>N
log<sub>b</sub>b = 1
log<sub>b</sub>1 = 0
log<sub>b</sub>b<sup>k</sup> = k


What Keypad posted, but tidied up a bit (easier to read):
Log<sub>a</sub>b<sup>c</sup> = c * Log<sub>a</sub>b
Log<sub>a</sub>b = Log<sub>c</sub>b / Log<sub>c</sub>a
Log<sub>a</sub>b * Log<sub>b</sub>a = 1
a<sup>1/Log_b[a]</sup> = b
a = b<sup>Log_b[a]</sup>

Now they're right.
 

Grey Council

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whoops, a few typos by me. lol, shouldn't have just copied pasted to save time. :$ hehe
 

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