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Odd QueStiOn.. (1 Viewer)

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Q. Use the trapezoidal rule with 4 subintervals to find an approximation to the volume of the solid formed by rotating the curve y=cosx about the x-axis from x=0 to x=pi/2.

Finding volume with trapezoidal rule?Is that possible?Help please?

Thanks:)
 

Xayma

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A trapezium that is rotated will form a frustrum.

The volume of Frustrum is given by

V=h*pi/3 (R<sup>2</sup>+Rr+r<sup>2</sup>)

Where R is the radius of the lower base (ie the longer of the parallel sides)

and r is the radius of the upper base (ie the shorter of the parallel sides)
 

redslert

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trapezoidal rule to find volume?

i have never done a question like that before....

Xayma eer what are you on about?
his doing a cos curve?
 
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Originally posted by Xayma
A trapezium that is rotated will form a frustrum.

The volume of Frustrum is given by

V=h*pi/3 (R<sup>2</sup>+Rr+r<sup>2</sup>)

Where R is the radius of the lower base (ie the longer of the parallel sides)

and r is the radius of the upper base (ie the shorter of the parallel sides)
ummm....hmmm......are we supposed to know this formula??



Originally posted by redslert
his doing a cos curve?
heeyyy..."his"?? u refering to me?? I'm not a guy...:D
 
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Heinz

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Originally posted by +GriM ReApeR+
Q. Use the trapezoidal rule with 4 subintervals to find an approximation to the volume of the solid formed by rotating the curve y=cosx about the x-axis from x=0 to x=pi/2.

Finding volume with trapezoidal rule?Is that possible?Help please?

Thanks:)
I did it.. but I dont agree with the answer I got. My "approximation" was equal to the exact area received through direct integration (pi<sup>2</sup>/4). Either I made a mistake (very likely) or I mustve used a hell of a lot of intervals :p
 

Heinz

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Originally posted by +GriM ReApeR+
hey...that was the answer in the textbook...:D...smart smart!
hmm... well heres the working
 

kpq_sniper017

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i've often done questions asking for approximations for volumes using simson's or trapezoidal.

all u have to do is approximate the integral using simpson's and multiply it by pi and then that's ur approximate for the volume. i think they do it in maths in focus in the challenge exercises.
 

kpq_sniper017

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i did it on paper.....and i got an answer of pi<sup>2</sup>/4 which is approx. equal to 2.467u<sup>3</sup>

can somebody verify my answer?
 

kpq_sniper017

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Originally posted by pcx_demolition017
i did it on paper.....and i got an answer of pi<sup>2</sup>/4 which is approx. equal to 2.467u<sup>3</sup>

can somebody verify my answer?

lol.....just realised heinz already it. :)
 

Xayma

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Originally posted by redslert
Xayma eer what are you on about?
his doing a cos curve?
I know but he was doing the trapezoidal rule, and I forgot to just square it and then do the integral normally, so I fell back that a trapezoid that is rotated around a line will form a frustrum (ie a cone with the top bit cut off).

Heinz isnt that 5 subintervals?
 
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Heinz

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Originally posted by Xayma
I know but he was doing the trapezoidal rule, and I forgot to just square it and then do the integral normally, so I fell back that a trapezoid that is rotated around a line will form a frustrum (ie a cone with the top bit cut off).

Heinz isnt that 5 subintervals?
4 subintervals = 5 function values
 

Xayma

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oh yeah, I though subinterval sounded wrong (I was thinking function values)
 

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