V velox Retired Joined Mar 19, 2004 Messages 5,521 Location Where the citi never sleeps. Gender Male HSC N/A Apr 4, 2004 #1 Hey, this is prob a really dumb question but does every parabola in the form x^2= 4ay have its vertex as (0,0) ?? thanks!!!
Hey, this is prob a really dumb question but does every parabola in the form x^2= 4ay have its vertex as (0,0) ?? thanks!!!
H ~*HSC 4 life*~ Active Member Joined Aug 15, 2003 Messages 2,411 Gender Undisclosed HSC N/A Apr 4, 2004 #2 Yes they all have vertex (0,0)
V velox Retired Joined Mar 19, 2004 Messages 5,521 Location Where the citi never sleeps. Gender Male HSC N/A Apr 4, 2004 #3 thanks
Calculon Mohammed was a paedophile Joined Feb 15, 2004 Messages 1,743 Gender Undisclosed HSC N/A Apr 4, 2004 #4 otherwise its x<sup>2</sup>=4ay+c where c is a constant
C CM_Tutor Moderator Moderator Joined Mar 11, 2004 Messages 2,644 Gender Male HSC N/A Apr 4, 2004 #5 Or in a more general form, (x - h)<sup>2</sup> = 4a(y - k) has a vertex at (h, k).
W Winston Active Member Joined Aug 30, 2002 Messages 6,128 Gender Undisclosed HSC 2003 Apr 4, 2004 #6 http://www.boredofstudies.org/community/showthread.php?s=&threadid=27070 check this thread, i've replied with quite a brief summary of what you should know about the Parabola in terms of the Locus topic. I explained about the parabola at vertex (0,0) or at vertext (h,k)
http://www.boredofstudies.org/community/showthread.php?s=&threadid=27070 check this thread, i've replied with quite a brief summary of what you should know about the Parabola in terms of the Locus topic. I explained about the parabola at vertex (0,0) or at vertext (h,k)
C Collin Active Member Joined Jun 17, 2003 Messages 5,084 Gender Undisclosed HSC N/A Apr 6, 2004 #7 The parabola, by definition is a locus anyway; eccentricity = 1.