R rsingh Member Joined Oct 2, 2004 Messages 186 Gender Male HSC 2005 Aug 27, 2005 #1 For the parabola, x^2=6y+3, Find the coordinates of its focus and the equation of its directrix. I was just wondering, can you factorise like this and do it? x^2=6(y+0.5)
For the parabola, x^2=6y+3, Find the coordinates of its focus and the equation of its directrix. I was just wondering, can you factorise like this and do it? x^2=6(y+0.5)
香港! Member Joined Aug 24, 2005 Messages 467 Location asdasdas Gender Undisclosed HSC 2010 Aug 27, 2005 #2 rsingh said: For the parabola, x^2=6y+3, Find the coordinates of its focus and the equation of its directrix. I was just wondering, can you factorise like this and do it? x^2=6(y+0.5) Click to expand... yehhh den use x²=4a(y-k) so vertex is (0,-1\2) focal length a=3\2 so focus is at (0, -1\2+3\2) directrix: y=-1\2-3\2
rsingh said: For the parabola, x^2=6y+3, Find the coordinates of its focus and the equation of its directrix. I was just wondering, can you factorise like this and do it? x^2=6(y+0.5) Click to expand... yehhh den use x²=4a(y-k) so vertex is (0,-1\2) focal length a=3\2 so focus is at (0, -1\2+3\2) directrix: y=-1\2-3\2
R rsingh Member Joined Oct 2, 2004 Messages 186 Gender Male HSC 2005 Aug 27, 2005 #3 Thanks for your help man!
