Plz Check my answer and workin out to see if its correct thanks (1 Viewer)

[sando]

Calculate the mass of solid hydrogen carbonate required to make 250mL of 0.12 mol solution

This is how i got my answer:

# mol = mass/Molar Mass

0.12= mass/Molar Mass X volume

mass= 0.12/84 X .250

mass= 10.08 X .25

therefore mass= 2.52 g of solid hydrogen carbonate

can someone just check to see if this is all right, cos i dont hav the answers as i am practicing a 2004 paper

 

[Riviet]

You got confused with number of moles and molarity (concentration).

n_{(hydrogen carbonate)}=cV
=0.12x0.25
=0.03 mol.

n=m/mm
.'. m=n x mm
=0.03 x (1+12+16+16+16)
=1.83 g

By the way, good luck with chemistry tomorrow!

 

[pLuvia]

c=n/V
0.12=n/0.25
n=0.03

n=m/M
0.03=m/62.03
m=1.86g

 

[sando]

You got confused with number of moles and molarity (concentration).

n_{hydrogen carbonate}=cV
=0.12x0.25
=0.03 mol.

n=m/mm
.'. m=n x mm
=0.03 x (1+12+16+16+16)
=1.83 g

By the way, good luck with chemistry tomorrow!

AHHH!!! i hate how i mix them up

and thanks, im going to need all the luck i can get
good luck 2 u 2