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Probability Question (1 Viewer)
- Thread starter smithjohn
- Start date
pikachu975
Premium Member
P(at most 2 heads) = P(0 heads) + P(1 head) + P(2 heads)
= P(3 tails) + P(2 tails) + P(1 tail)
= 36/100 + 29/100 + 20/100
= 17/20 (not an option)
But I think the question has a typo because it says "counting the number of heads" is the experiment and the table has "number of tails". I think it's meant to have "number of heads" which then becomes:
P(at most 2 heads) = P(0 or 1 or 2 heads)
= 15/100 + 20/100 + 29/100
= 16/25 (B)
= P(3 tails) + P(2 tails) + P(1 tail)
= 36/100 + 29/100 + 20/100
= 17/20 (not an option)
But I think the question has a typo because it says "counting the number of heads" is the experiment and the table has "number of tails". I think it's meant to have "number of heads" which then becomes:
P(at most 2 heads) = P(0 or 1 or 2 heads)
= 15/100 + 20/100 + 29/100
= 16/25 (B)
