probability (1 Viewer)

[dawso]

i got this question out of a past half yearly from my school and i swear there must be a typo in it cause its weirdly hard....

also, for all u sydney peoples, mind the hawks references, cause they do rule, and they will kill you in the remaining 3 games (or maybe not, we are playin like shit) also, to the basketball fans, just excuse the impossibility of this question as basketball shirts never would be numbered 1-10 as all numerals used must be able to be shown by the ref's fingers.... (1-5)

QUESTION:

IN a mix up at the hawks basketball match, the shirts arrive in 2 boxes, the first contains 3 black shirts and 7 white shirts while the second box contains 2 white shirts and 8 black shirts, each set of shirts is numbered from 1-10.

The coach Brendan Joyce arrives and gets the 10 players to put on the black shirts, they all stand in a circle. What is the probability that the numbers are all in numerical order around the circle...?

thanx in advance

GO THE HAWKS!!

 

[KFunk]

Seems like the biggest difficulty is in interpretation. I geuss I'd assume that the team would not consider picking a white shirt and that the selection is only made from the blacks.

So then we have to find the likelihood of the black T-shirts having the numbers which would make a full set of 1-10, the probability of picking the said set then I geuss it's the probability of this 1-10 set arranging around the circle in order.

I don't like their chances...




EDIT: So thinking about it.

1. The probability of the second set of 8 blacks complimenting the first set of 7 blacks
= 1 - P(not complimenting)
= 1 - 3/10x2/9
= 14/15 since set-1 requires three shirts from set-2


2. and probability of the first set of 7 blacks complimenting the second of 8 blacks
= 1 - 2/10x1/9
= 44/45

(I think there's more to this particular step [2] but I can't be bothered, I'll just do the gist of how I figure it works)


3. The odds of picking one through 10.... oh, doubles of a particular number... ok screw this, I'm tired.

Would permutations and combinations help out in this? 'cause I think there's a probability bit in that. I might have a proper go at this later when I'm less lazy