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Proof of normal to hyperbola (1 Viewer)

edd91

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Can someone write out the complete proof for me, i cant get to the 'standard' equation
 

Teoh

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Just differentiate the equation of the normal hyperbola to find gradient of tangent
Reciprocate that, and use two point formula with cartesian or paramteric co-ordinates to give you equation.
 

Heinz

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Originally posted by Teoh
Just differentiate the equation of the normal hyperbola to find gradient of tangent
Reciprocate that, and use two point formula with cartesian or paramteric co-ordinates to give you equation.
You mean minus the reciprocal of the gradient ;)
 

edd91

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parametric form
I know the process to get to it but I just cant??I get to this:

-xy1/a^2 + yx1/b^2= -yx/b^2 - xy/a^2

then dont know how to get to my target
 

grimreaper

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Originally posted by edd91
parametric form
I know the process to get to it but I just cant??I get to this:

-xy1/a^2 + yx1/b^2= -yx/b^2 - xy/a^2

then dont know how to get to my target
Erm well you've done something wrong because thats wrong... try doing it again. You should end up with an x1^2/a^2 and a y1^2/b^2, which when you subtract the second from the first = 1
 

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