MedVision ad

Prove that there is no greatest even integer (1 Viewer)

SB257426

Very Important User
Joined
Jul 12, 2022
Messages
309
Location
Los Alamos, New Mexico, USA
Gender
Male
HSC
2023
Is this how I should complete my proof:

By way of contradiction assume that 2k is the largest even integer.

Now consider (2k)!

(2k)! = (2k)(2k-1)(2k-2).......(k)(k-1)(k-2)......(2)(1)

= 2[k(2k-1)(2k-2).......(k)(k-1)(k-2)......(2)(1)]

= 2p, which is also an even integer. This contradicts the fact that 2k was the largest even integer. Therefore it is sensible to claim that there is no even integer since 2p>2k
 

tywebb

dangerman
Joined
Dec 7, 2003
Messages
2,182
Gender
Undisclosed
HSC
N/A
If you assume if it exists then it is 2k for an integer k.

But then I'd be more inclined just to add 2.

So now 2k+2=2(k+1) is a bigger even integer - contradiction there is no biggest even integer.
 
Last edited:

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top