MedVision ad

Quantitative chemistry (1 Viewer)

hs17

Member
Joined
Mar 1, 2020
Messages
95
Gender
Female
HSC
2021
Screen Shot 2020-05-17 at 12.45.59 pm.png
The answers in the textbook are a bit off with the rounding...so could someone please do part b) ?
 

Pedro123

Active Member
Joined
Jun 17, 2019
Messages
106
Gender
Male
HSC
2021
Mol of H2S =

Mol of SO2 =

This means that since the ratio should be 2:1, andn since 0.469/2 = 0.235 (Rounding), the H2S is the limiting reagent.
This means remaining SO2 = 0.312 - 0.469/2 = 0.077
As such, the remaining mass is 0.077*(16*2+32.065) = 4.93 grams of SO2(3 S.F)

Apologies for all the edits - I am a bit dumb and didn't realise the SO2 wasn't 2SO2
 
Last edited:

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top