question 2 (1 Viewer)

[expertise123]

for question 2 v. which area did u have to shade and what was the equation of the line e.

 

[JamiL]

i think uit was l not e n im sure it was under unless were thinkin of different qu

 

[bevstarrunner]

<img src="http://img44.exs.cx/img44/6114/2avgraph.jpg" alt="Image Hosted by ImageShack.us" />
including the line

line 'e' or l i think it was, was x=2

 

[A2RAYA]

<img src="http://img44.exs.cx/img44/6114/2avgraph.jpg" alt="Image Hosted by ImageShack.us" />
including the line

line 'e' or l i think it was, was x=2

yeh it was x=2 for the equation..but wasnt the shaded area everything below the x axis only?...crap wat was i thinking then?

also wat were the coordinates of C...i know the x value was 2 cos of the lin l but wtf was the y vlue...i had no clue for sum reason, totally blanked out

 

[coroneos]

yea wtf.. the shaded area is the bit under y=0 .... lol

 

[Gobbie_7]

I got the co-ords of C to be (2,3). But just looking at the question, i think it is wrong.

 

[bevstarrunner]

If u plug in any coordinate in the 'blue' section the inequality is satisfied

c was at (2,6)

You need to work out the equation of line AC, which is perpendicular to AB, so m=1.
then u go:
y - 3 = 1(x - (-1)
x - y + 4 = 0
then u plug in x = 2
2 - y - 4 = 0
y = 6