scaryshark09
∞∆ who let 'em cook dis long ∆∞
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- 1999
they should have solutions..View attachment 40539
How do you do part (ii) and (iii) please?
ive either never heard of this identity or forgot about it. is it in the cambrige textbook?ii) is just the identity where modulus square is the complex and the complex conjugate multiplied and then u get that basically. (PAk is the same as AkP so u get P - Ak which is Z - wk)
for both II and III can you use the |z|^2 identity? (ie |z|^2=z*z(conjugate))?View attachment 40539
How do you do part (ii) and (iii) please?
Its apparently something ppl always manage to forget in 4u. similar to that triangle inequality thingo (NOTE I DONT MEAN THE IDENTITY IS RELATED TO IT, IM SIMPLY SAYING THAT ITS AS FORGOTTEN AS THE TRIANGLE INEQUALITY)ive either never heard of this identity or forgot about it. is it in the cambrige textbook?
why does PAk = z-wk tho?View attachment 40539
How do you do part (ii) and (iii) please?
dw about this i just made a mistakeView attachment 40541
for part (iv), i did the intgration without bounds and did the plus c thing, and then subed values in to find c. In this case it didn't work. Can someone explain why you have to integrate with bounds for part (iv), or is there something i am missing?
what mark did.u get
Yes, the identity is in all the texts, and is easily proved.ive either never heard of this identity or forgot about it. is it in the cambrige textbook?