The altitude of a right-angled triangle is 6 cm and the base is increasing at a constant rate of 2cm/s. At what rate it the hypotenuse increasing when its length is 10 cm?
No idea how to do this question. But i did approach it. I tried using similar triangles but it didn't work out. Why?
Let length be y and base be x
At y=10
6/y = x/h
6/10 = x/h
x = 3/5 h
dx/dt = 3/5 dh/dt
thus dh/dt = 10/3 cm/s
The actual answer is 1.6
No idea how to do this question. But i did approach it. I tried using similar triangles but it didn't work out. Why?
Let length be y and base be x
At y=10
6/y = x/h
6/10 = x/h
x = 3/5 h
dx/dt = 3/5 dh/dt
thus dh/dt = 10/3 cm/s
The actual answer is 1.6
