Reflection Theory (1 Viewer)

[BoredDude]

So... does anyone want to inform me what the reflection theory is?

 

[apollo1]

So... does anyone want to inform me what the reflection theory is?

haha no idea.

 

[lpodnano]

LOL. I just made that as a fake reason haha.
______ (reflection theory)

Honestly no idea haha

 

[HyperComplexxx]

is it like that ?

 

[Hayzazz]

It was this:

The two angles in red are equal

 

[slyhunter]

I figured out what the theory was an hour after I looked at the question haha.

 

[BoredDude]

Oh I see now... Now it makes perfect sense...

 

[Riku123123]

shoot i forgot Dx

 

[roryclifford]

when you did it could you just assume it? is that what it meant, so then you proved triangles congruent etc??
or did you have to prove the property haha

 

[hscishard]

Oh snap. That's the reflection theory. Learnt it with the parabola in a year 11 book but not for 4unit wtf.

 

[Hayzazz]

Naa the question said "Use the reflection property" so you assume it.

 

[apollo1]

Naa the question said "Use the reflection property" so you assume it.

yay. i just said using the reflection property without knowing wat the fuck it was.

 

[AAEldar]

yay. i just said using the reflection property without knowing wat the fuck it was.

I did virtually the same thing with a couple other things about it >.<

 

[UnrealAnchovies]

it's a very specific dot point in the syllabus

deriving it is a hell of a lot of algebra, but simple algebra nonetheless

 

[CombustionManX]

I had no idea what it was, I just assumed that by using it I could figure out that <PSQ=<PRQ so I went:

By inspection, using the reflection property of the ellipse <PSQ=<PRQ
Then I proved that triangles PSQ and PQR were congruent (equiangular) and equated the congruent sides.

Basically, I By Inspection'd it like a boss.

 

[hup]

I had no idea what it was, I just assumed that by using it I could figure out that <PSQ=<PRQ so I went:

By inspection, using the reflection property of the ellipse <PSQ=<PRQ
Then I proved that triangles PSQ and PQR were congruent (equiangular) and equated the congruent sides.

Basically, I By Inspection'd it like a boss.

equiangular =/= congruent

 

[khorne]

You could have stated the perpendicular from the vertex to the base bisects the base in an isos triangle. Much quicker

 

[rawrence]

We didn't need to derive it did we? Like we could just assume it right??

 

[Hayzazz]

We didn't need to derive it did we? Like we could just assume it right??

Yes you could just assume it

 

[AAEldar]

You could have stated the perpendicular from the vertex to the base bisects the base in an isos triangle. Much quicker

I said exactly that.