1. a(-1)^2-b(-1)-10=0 and a(5)^2-b(5)-10=0
then solve simultaneous equations
2. let the roots be A and 3A
sum of roots, A+3A=4A=-q
so A=-q\4
product of roots, (A)(3A)=3A²=r
For question 1, I find it quicker to do these questions like this:
(x+1)(x-5)=0
x<sup>2</sup>-4x-5=0
2x<sup>2</sup>-8x-10=0
a=2; b=8.
Rather than doing simultaneous equations.