alrite
so here the question
a cable has a resistance of 0.06ohm perkm. what is teh max distance over which 500000w of power can be transmitted with 10% of loss at 600kv?
so here is wat i did
P=VI 500000=600000*I
I=5/6(amps)
heat loss is P=I^2 R
p=(5/6)^2 * 0.06
p=0.7*0.06
P=0.042(watt) loss per km
500000*0.1=50000(w)
so if we were to lose 50000(watts) of power it will take
50000/0.042=1200000(km)
, did i just solve it? i was gonna ask you people. can anybody confirm if this is correct?
so here the question
a cable has a resistance of 0.06ohm perkm. what is teh max distance over which 500000w of power can be transmitted with 10% of loss at 600kv?
so here is wat i did
P=VI 500000=600000*I
I=5/6(amps)
heat loss is P=I^2 R
p=(5/6)^2 * 0.06
p=0.7*0.06
P=0.042(watt) loss per km
500000*0.1=50000(w)
so if we were to lose 50000(watts) of power it will take
50000/0.042=1200000(km)
, did i just solve it? i was gonna ask you people. can anybody confirm if this is correct?
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