3U CSSA Trial (1 Viewer)

[Aquawhite]

what does it have to do with what i said?

you said 80+/84 is o k a y...

I'd probably scream like a crazy asian anime girl if I got 80+/84 in the MX1 exam...

 

[Bdogz]

how did ppl do that last probability quest part i) quest 7, did u hv 2 use (a+b)^n=50C25..........?i think im lost:mad1:

 

[Bdogz]

btw is high 40s-50 out of 84 a good mark 4 3unit?

 

[crystalfishy]

lyounamu can you tell me how did u find k for the rate of change please?

 

[-Onlooker-]

Bdogz, high 40's low 50's /84 is shit; But it depends on what ATAR your aiming for. . . .

If you're aiming for 85, It's reasonable
95, You need to step it up
99, No chance.


And to the person above me. I am not lyounamu but...
Find dSA/dt; and equate to 0.1 and solve for k, and Voila, you get your answer ( which is 2 btw )

 

[M@ster P]

Bdogz, high 40's low 50's /84 is shit; But it depends on what ATAR your aiming for. . . .

If you're aiming for 85, It's reasonable
95, You need to step it up
99, No chance.


And to the person above me. I am not lyounamu but...
Find dSA/dt; and equate to 0.1 and solve for k, and Voila, you get your answer ( which is 2 btw )

High 40s and low 50s is not shit, a bit harsh, high 40s and lows 50s i reckon is above state average, i reckon state average is like in the 30s.

High 40s and low 50s will probably be 40/50

 

[crystalfishy]

Bdogz, high 40's low 50's /84 is shit; But it depends on what ATAR your aiming for. . . .

If you're aiming for 85, It's reasonable
95, You need to step it up
99, No chance.


And to the person above me. I am not lyounamu but...
Find dSA/dt; and equate to 0.1 and solve for k, and Voila, you get your answer ( which is 2 btw )

thx and did u manage theprove bla bla = tan^2x question ??

 

[5647382910]

Bdogz, high 40's low 50's /84 is shit; But it depends on what ATAR your aiming for. . . .

If you're aiming for 85, It's reasonable
95, You need to step it up
99, No chance.


And to the person above me. I am not lyounamu but...
Find dSA/dt; and equate to 0.1 and solve for k, and Voila, you get your answer ( which is 2 btw )

I really hope it was 2 because i came out of the exam asking eveyone what they got and they all said k = 1

 

[5647382910]

thx and did u manage theprove bla bla = tan^2x question ??

lmao, i spent ages (about 7 minutes) trying to simplify my sin and cos soup, to then realise the t method which got me the answer

 

[mwah015]

i got 110 for the circle geometry question... i dunno if its ryt

 

[ratcher0071]

i got 110 for the circle geometry question... i dunno if its ryt

Yes it is

 

[crystalfishy]

lmao, i spent ages (about 7 minutes) trying to simplify my sin and cos soup, to then realise the t method which got me the answer

can you tell me how to do it?
was the question
tan2x + tanx
----------------
tan2x + cotx

show = tan^2x?

 

[ratcher0071]

can you tell me how to do it?
was the question
tan2x + tanx
----------------
tan2x + cotx

show = tan^2x?

just change the tan2x into its single angle formula and cotx to 1/tanx
then just simplify

 

[Aquawhite]

lyounamu can you tell me how did u find k for the rate of change please?

I did it...

Just using the basic rates of change formula's ... the normal set out.

 

[Aquawhite]

can you tell me how to do it?
was the question
tan2x + tanx
----------------
tan2x + cotx

show = tan^2x?

I stuffed that one up... I wish I simply had remembered the result properly and I wouldn't have thrown 3 marks away.

 

[Bdogz]

High 40s and low 50s is not shit, a bit harsh, high 40s and lows 50s i reckon is above state average, i reckon state average is like in the 30s.

High 40s and low 50s will probably be 40/50

oh k thnx,
how did u guys do the last probability question
?

 

[crystalfishy]

just change the tan2x into its single angle formula and cotx to 1/tanx
then just simplify

can you show me? i couldnt get it...maybe i wrote question wrong?


EDIT: is the sign ontop a "-" insetad of a "+" if so then i can do it... i think i copied it wrong..zomgg no wonder i couldnt get it in exam =[

 

[Dumbledore]

what did u get for the last projectile question?
i expressed the equation as a quadratic in terms of tan@ but when i used the quadratic formula, it didn't simplify

 

[crystalfishy]

meh..i hope 76+/84 (90%)

 

[the-derivative]

hmm answer is 2x3^n isnt it

Q: [(2^4n x 3^2n)/ (8^n x 6^n)] + 3^n

2^4n x 3^2n
------------------------ +3^n
2^3n x 3^n x 2^n

cancel...
u get 3^n + 3^n = 2 x 3^n

I remember getting something like that

just change the tan2x into its single angle formula and cotx to 1/tanx
then just simplify

Yeah I expanded using normal double angle and simplified. At first I tried changing to sin and cos but that screwed me over, so I ended up playing with just tans and i got it.