How do you differentiate this? (1 Viewer)

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Dec 20, 2008
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x^2+2xy+3y^2=18

d(x^2+2xy+3y^2)/dx=d(18)/dx

dx^2/dx + d(2xy)/dx + 3y^2/dx = 0

2x + d(2x)/dx . y + dy/dx . x + d(3y^2)/dy = 0
2x + 2y + xy' + 6y= 0
xy' = -8y - 2x
y'= -8y-2x/x

.....think thats wrong lolol.
 

RaxX

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Nov 14, 2009
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2011
ill do it if you want and scan it up.
 

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