Max/Min problem (1 Viewer)

[talbot777]

ok guys got this problem part one requires you to show the area is

A= x/2 [squareroot (25-x^2)]^1/2

i can get that but i cant differentiate this and solve for when the first derivative = 0. would someone be able to show how its done?

 

[talbot777]

thats what you have to differentiate then find the max x value

 

[x_symphonic]

got the answer by any chance. And are you sure theres a square root + power of another 1/2?

 

[x_symphonic]

thats what you have to differentiate then find the max x value

oh alright. lme c

 

[talbot777]

yeh sorry i realised it was hard to understand. so i used the equation thing to make it clearer

 

[x_symphonic]

does x = (25/2)^1/2?

 

[x_symphonic]

this is what i got

http://img705.imageshack.us/img705/8880/img021wu.jpg

and depending on what x is, it could be negative. if its length then its only pos+

 

[talbot777]

thankyou that is correct now just to make sense of your working

 

[x_symphonic]

thankyou that is correct now just to make sense of your working

np

 

[davidyin92]

Yeap, should really rationalise the denominator.