2x Maths Questions (1 Viewer)

Varin9

Member
Joined
Jun 1, 2010
Messages
72
Location
Kellyville
Gender
Male
HSC
2011
Simutaneous Equations
Find real numbers for p,q,r-

p^2 + q^2 + r^2 = 3
p + q + r =1
p + 2q - r = 5

(just a thought, but i you square each term in the second one, it doesnt seem to work)

Solve for x and y

x + y * root2
------------- = root2
root2 - 1

Thanks in advance to everyone appreciate it
 

Alkanes

Active Member
Joined
May 20, 2010
Messages
1,417
Gender
Male
HSC
2012
umm is the answer for the second question x = 2 and y = -1? ill post up the solution if its right =)
 

SpiralFlex

Well-Known Member
Joined
Dec 18, 2010
Messages
6,960
Gender
Female
HSC
N/A
Disregard question fixing it soon

Let's add equation 2 and 3

p + q + r + p + 2q - r = 1 + 5

2p + 3q = 6 [Equation 4]

Now, let's minus equation 3 from 2

p + q + r - (p + 2q - r) = -4 Equation 5

-q + 2r = -4 [6]

Let's focus on equation [4] and [6]

2p + 3q = 6

- q + 2r = 4

Let's times [6] by 3

-3q + 6r = -12 [7]

[4] + [7]

2p + 6r = -6

Hence, p + 2r = -3

Change the subject for 2r: 2r = -3 - p [8]

Substitute this into equation [6]

-q + 2(-3-p) = -4

-q - 6 - 2p = -4

-q - 2p = 2 [9]

[4] + [9]

2q = 8

q = 4

Sub for the rest: you should get q = 1, p =

To be completed soon

Give me a second to finish this.

2nd one: times all sides by root 2.

2 - sqrt(2) = x + y sqrt 2

By the theorem of surds, x must be 2, y = -1 no matter what.
 
Last edited:

Varin9

Member
Joined
Jun 1, 2010
Messages
72
Location
Kellyville
Gender
Male
HSC
2011
回复: Re: 2x Maths Questions

Still working on first one.

2nd one: times all sides by root 2.

2 - sqrt(2) = x + y sqrt 2

By the theorem of surds, x must be 2, y = -1 no matter what.
Yeah i though that, thx, but the one that has me stumped is the first one.
 

SpiralFlex

Well-Known Member
Joined
Dec 18, 2010
Messages
6,960
Gender
Female
HSC
N/A
Re: 回复: Re: 2x Maths Questions

Hold on mate, i'm trying to do it, it's taking long.
 

jyu

Member
Joined
Nov 14, 2005
Messages
623
Gender
Male
HSC
2006
p^2 + q^2 + r^2 = 3
p + q + r =1
p + 2q - r = 5

Please check the equations
 

AAEldar

Premium Member
Joined
Apr 5, 2010
Messages
2,246
Gender
Male
HSC
2011
Just solved it.



Or



Will post working up in a sec.
 

SpiralFlex

Well-Known Member
Joined
Dec 18, 2010
Messages
6,960
Gender
Female
HSC
N/A
I'm sure I have seen this in one of the Cambridge books. Can you check if you typed equations right?
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top