Method 1: Use circle geometry-> Angle subtended by a chord at the centre is twice the angle subtended at the circumference. Method 2: Angle OCA = theta as triangle OCA is isoceles. Therefore angle POC= 2x theta (exterior angle of a triangle) Method 3: Angle ACB= 90 degrees (angle in a semicircle). Therefore angle CBA=90-theta (angle sum of triangle). Angle OCB also equals 90-theta (triangle OBC is isoceles). Therefore angle POC = 2x theta (angle sum of triangle)
Thanks, you mean the triangle above is a right angle one right? Yea got that. I proved PCB but trying to figure out POC
omg! thx! I totally forgot about the radii lol
Thanks, you mean the triangle above is a right angle one right? Yea got that. I proved PCB but trying to figure out POC
omg! thx! I totally forgot about the radii lol