Help?!

[zannasheayarrow]

Where do you expect a gap in the graph y=x+1/(x-1)? Would it be x=1????

 

[funnytomato]

yes, there is a 'vertical asymptote' at x=1

besides, there is a 'horizontal asymptote' at y=1 as x tends to +ve/-ve infinity

 

[zannasheayarrow]

is y=x also an asymptote?

 

[jet]

There's no horizontal asymptote, and yes y = x is an asymptote.

 

[Carrotsticks]

There's no horizontal asymptote, and yes y = x is an asymptote.

Oh dear, all this April Fooling is going to put off a lot of students...

 

[asianese]

lol

y= x+1/x-1 = x-1+2/x-1 = 1+ 2/x-1

So draw 2/x-1 and shift it up 1 unit.

 

[Timske]

Oblique asymptote

 

[SpiralFlex]

This graph is obviously a parabola going through the point (0,0).

April fools!