goobi
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- 2012
Simple Harmonic Motion
This is a question from Math in Focus.
The period of a particle moving in *EDIT* SHM is 6s and its amplitude is 8cm. Calculate its velocity and acceleration (correct to 1 decimal place) when the displacement is 5cm from the centre of the motion.
Okay so these are what I've done so far:
![](https://latex.codecogs.com/png.latex?\bg_white Period=\frac{2\pi}{n}=6)
![](https://latex.codecogs.com/png.latex?\bg_white n=\frac{\pi}{3})
![](https://latex.codecogs.com/png.latex?\bg_white v^2=n^2(a^2-x^2))
![](https://latex.codecogs.com/png.latex?\bg_white v^2=(\frac{\pi}{3})^2(8^2-x^2))
![](https://latex.codecogs.com/png.latex?\bg_white v=\pm%20\sqrt{\frac{13\pi^2}{3}})
(cor. to 1 d.p.)
However, the problem is I don't understand why the textbook takes the negative sign (i.e. -6.5 cm/s) instead of the positive sign. I thought the velocity was supposed to be in the same direction as the displacement (i.e +5cm as given)? Correct me if I am wrong.
Any help would be greatly appreciated![Smile :) :)](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
This is a question from Math in Focus.
The period of a particle moving in *EDIT* SHM is 6s and its amplitude is 8cm. Calculate its velocity and acceleration (correct to 1 decimal place) when the displacement is 5cm from the centre of the motion.
Okay so these are what I've done so far:
However, the problem is I don't understand why the textbook takes the negative sign (i.e. -6.5 cm/s) instead of the positive sign. I thought the velocity was supposed to be in the same direction as the displacement (i.e +5cm as given)? Correct me if I am wrong.
Any help would be greatly appreciated
Last edited: