projectile question (1 Viewer)

[U MAD BRO]

i have the distance, speed and time, how do i calculate the acceleration of a person running :$
the runner has to cover a distance of 50.36m in 2.86s, so i need to calculate his constant acceleration.

 

[someth1ng]

Use the formula: s=ut+(1/2)at^2

The formula sheet will have a different notation and because it's a lot harder to remember, I used that one.

 

[U MAD BRO]

Use the formula: s=ut+(1/2)at^2

The formula sheet will have a different notation and because it's a lot harder to remember, I used that one.

what would u sub s with?
and is u 0m/s in this case? since it is horizontal?

 

[Rathaen]

s = displacement
u = initial velocity
a = acceleration
t = time

 

[someth1ng]

what would u sub s with?
and is u 0m/s in this case? since it is horizontal?

u=initial velocity, if they're starting rest rest then you sub in 0ms^-1
s=displacement, if they're starting from position 0m then the displacement at the end will be 50.36m
a and t are quite obvious.

Solution
s=50.36m
t=2.86s
u=0ms^-1

s=ut+(1/2)at^2
50.36=(0)(2.86)+(1/2)(2.86^2)a
a=[50.36]/[(1/2)(2.86^2)]
a=12.3ms^-2 in the initial direction

 

[U MAD BRO]

u=initial velocity, if they're starting rest rest then you sub in 0ms^-1
s=displacement, if they're starting from position 0m then the displacement at the end will be 50.36m
a and t are quite obvious.

thanks =)