Question! (1 Viewer)

[louielouiee]

Okay so, I always seem to mess up these questions, although they're not that hard.

Solve 2sinx = - root 3 for 0 < or equal to x <or equal to 2pi.

I got the answers x= 4pi/3 and 5pi/3

I'm just wondering how you know when you've got all the possible answers using the quadrants and stuff?
In some questions I can 2 answers, when there is actually 3, etc.

Thanks

 

[gr_111]

well you got that one right, so why don't you put up a question that you got wrong and we can maybe explain.

 

[louielouiee]

These harder ones:
root3 sinx -cosx =-1 for 0<equal to x <equal to 2pi

 

[Timske]

These harder ones:
root3 sinx -cosx =-1 for 0<equal to x <equal to 2pi

Pretty sure that requires 3u method