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Q13 (3 Viewers)

Rafy

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Discuss your answers to Q13 here.
 

megaman64

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what did u guys get for 13.a.ii and iii, the angel of abc and coordinates of n and also 13.b.ii (area of shaded region)
 

osak23

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q13a)ii) 34 degress

13b) ii) 64/3

c) iii) 17/35

what was anyones answer for a)iii
the co-ords of n
 

nirukk

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for 13/a/iii I found the perpendicular distance, then what ?
 

RealiseNothing

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for 13/a/iii I found the perpendicular distance, then what ?
Find gradient of AB

Hence since they are perpendicular, you can find gradient of CN.

Find equation of CN using co-ordinates of C.

Solved AB and CN simultaneously to find N.
 

Timske

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FUARK! i hope i get the 2/3 marks
 

nirukk

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Find gradient of AB

Hence since they are perpendicular, you can find gradient of CN.

Find equation of CN using co-ordinates of C.

Solved AB and CN simultaneously to find N.
Aw how come I didn't think that way..
 

Poops

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For 13b)ii) Do you find the integral of the top curve between 0 and 4, and minus the integral of the bottom curve between 0 and 4? Someone told me you had to slip it up :( Is this true?
 

Joey7

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For 13b)ii) Do you find the integral of the top curve between 0 and 4, and minus the integral of the bottom curve between 0 and 4? Someone told me you had to slip it up :( Is this true?
I got 21 1/3. I don't think you had to split it up.
 

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