+1q13a)ii) 34 degress
13b) ii) 64/3
c) iii) 17/35
what was anyones answer for a)iii
the co-ords of n
N (1,4) if i recall correctlyq13a)ii) 34 degress
13b) ii) 64/3
c) iii) 17/35
what was anyones answer for a)iii
the co-ords of n
q13a)ii) 34 degress
13b) ii) 64/3
c) iii) 17/35
Same as you,
yea i got this, not sure if its right(3,2)?
yep (3,2) fked up my calcs(3,2)?
Yepp, I THINK I got this.(3,2)?
yes was (3,2)(3,2)?
Find gradient of ABfor 13/a/iii I found the perpendicular distance, then what ?
Aw how come I didn't think that way..Find gradient of AB
Hence since they are perpendicular, you can find gradient of CN.
Find equation of CN using co-ordinates of C.
Solved AB and CN simultaneously to find N.
I got 21 1/3. I don't think you had to split it up.For 13b)ii) Do you find the integral of the top curve between 0 and 4, and minus the integral of the bottom curve between 0 and 4? Someone told me you had to slip it up Is this true?