yep. i got that19pi/72 units cubed?
yep. i got that19pi/72 units cubed?
The man is correct lol, BOSS19pi/72 units cubed?
sack your tutor mate, its definitely k>32.the answer is k<-32, you draw a horizontal lone (k=-32) which is the last time the line intersects the quartic as it is the min y value thus under it there are no graphical solutions due to no intersections. i did a similar question with my tutor the day before the exam :L
Lmaoo seeing that he does 2u maths (from his sig), he doesn't even have maths tutoring anymoresack your tutor mate, its definitely k>32.
(1,-5) minthe graph didn't work for me, l got a min at 0,0 and a max at -1,-5 and a max at -2,-32 so l just... drew it l guess
l'm guessing l got it wrong so that's 20 marks gone in total.
wow.
never gonna underestimate an exam again.
stupid silly mistakes.
Def correct .(1,-5) min
(0 , 0) max
(-2,-32) mini
thats what i got
This.(1,-5) min
(0 , 0) max
(-2,-32) mini
thats what i got
how did u get 0,0 as a maximum i couldnt differentiate it as a maximum or minimum so i wrote point of inflection T_T(1,-5) min
(0 , 0) max
(-2,-32) mini
thats what i got
Well there are two ways you could do this; differentiate again or simply sub in values to the left and right of 0.how did u get 0,0 as a maximum i couldnt differentiate it as a maximum or minimum so i wrote point of inflection T_T
what was the equation again i remember differentiating again and getting 0 might have been a silly mistakeWell there are two ways you could do this; differentiate again or simply sub in values to the left and right of 0.
forgotwhat was the equation again i remember differentiating again and getting 0 might have been a silly mistake
It was definately a minimum.I got -2,-32 as a H.P.I. ????