swear it was D when I read it but k. fast edit ;pcan't you read? -.-
^7 is wrong forgot the negative but for 5, IF cl together is 2 factorial (as a group) x 6!
exactly , that's A!x-coordinate:
mx2+nx1/m+n
therefore (24-4)/5
therefore 20/5
therefore 4
... wrong?
i got same as u for 5, im pree sure its right.4 and 5 wrong
1 is C. Use Wolfram if you want proof.It was pretty good! so happy, can someone confirm my answers to MC:
- D
- A
- B
- C
- C
- A
- C
- D
- D
- B
5 is Ci got same as u for 5, im pree sure its right.
5 is D. 2*6!1 is C. Use Wolfram if you want proof.
2 is correct.
3 is correct.
4 is correct.
5 I put D, but I'm terrible at probability so you're probably correct. I figured there are 7 total letters but L and C only count as one, so 2 (ways of LC) * 6! (total of 6 objects)
6 is correct.
7 is correct.
8 is probably correct, I missed it until the last second and accidentally circled B because I couldn't see the question.
9 is correct.
10 probably correct.
yeah ?? so it is C!4: If its C then the amplitude is indeed 2 but the period is 6pi, meaning it would be restricted to 3pi, not 3pi/2
5: Group the C and L together so theres 6! ways of arranging those letters but the C and L can move in between each other 2 ways, hence 2 x 6!, so D
therez total 7, C L = 2! rest 5=5!4: If its C then the amplitude is indeed 2 but the period is 6pi, meaning it would be restricted to 3pi, not 3pi/2
5: Group the C and L together so theres 6! ways of arranging those letters but the C and L can move in between each other 2 ways, hence 2 x 6!, so D
No, I said IF it was C then it would be 6pi and be restricted to 3pi, but its restricted to 3pi/2 so it ends up being Dyeah ?? so it is C!
no, LlamaBoi is correcttherez total 7, C L = 2! rest 5=5!
therefore = 2 x 5!
Awesome. The suckiest person ever at probability got one right.5 is D. 2*6!
OLYMPIC - 7 LETTERStherez total 7, C L = 2! rest 5=5!
therefore = 2 x 5!