Prove LHS = RHS (1 Viewer)

[AnimeX]

Hi guys, I'm stuck on two questions for proofs. Please help

How would you prove that the left hand side is equal to the right hand side of the equation?

These are where I'm at in proving some mathematical induction results.

2) http://latex.codecogs.com/gif.latex?(1+2+...+k^2)+(k+1)^3&space;=&space;(1+2+...+k+k+1)^2




Don't worry about this one: I messed it up,

1) http://latex.codecogs.com/gif.latex?(\frac{1}{4}k^2(k+1)+k+1)^2%20=%20\frac{1}{4}(k+1)^2(k+2)^2

 

[Trebla]

Type the code on the main site and see if it comes up working. Once you know the code you can paste it here and wrap with [ tex ] and [ / tex ] (without the spaces). Alternatively, you can manually type it here.

 

[AnimeX]

Type the code on the main site and see if it comes up working. Once you know the code you can paste it here and wrap with [ tex ] and [ / tex ] (without the spaces). Alternatively, you can manually type it here.

I've already closed the Latex editor



edit: cool it works I'll try that for next time, thnx Trebla.

 

[D94]

You can add tags to the url, or alternatively, remove the [url]http://latex.codecogs.com/gif.latex?[/url] part and add the [tex] tags to the rest of the code. You don't need the LaTeX editor to do that.

1) [tex](\frac{1}{4}k^2(k+1)+k+1)^2%20=%20\frac{1}{4}(k+1)^2(k+2)^2[/tex]

2) [tex](1+2+...+k^2)+(k+1)^3&space;=&space;(1+2+...+k+k+1)[/tex]

 

[AnimeX]

can anyone help with Q ?

 

[asianese]

Induction?

 

[Trebla]

You can add tags to the url, or alternatively, remove the [url]http://latex.codecogs.com/gif.latex?[/url] part and add the [tex] tags to the rest of the code. You don't need the LaTeX editor to do that.

1) [tex](\frac{1}{4}k^2(k+1)+k+1)^2%20=%20\frac{1}{4}(k+1)^2(k+2)^2[/tex]

2) [tex](1+2+...+k^2)+(k+1)^3&space;=&space;(1+2+...+k+k+1)[/tex][/QUOTE]
Are you sure the first one is correct? The LHS is a polynomial of degree 6 and the RHS is a polynomials of degree 4.

 

[AnimeX]

Are you sure the first one is correct? The LHS is a polynomial of degree 6 and the RHS is a polynomials of degree 4.

damn, I stuffed up an earlier part of the question..

forget about the first one then =S, assumed it was right cause I tried k=2 and it worked, but when I tried k=3 it didn't soo yeahh silly me.